Question from Le:

Three vertices of parallelogram ABCD are A(6,3), B(3,8) and C(-6,10). If point D lies in quadrant II, find the coordinates of D.

Would anyone like to give it a go?

Question from Le:

Three vertices of parallelogram ABCD are A(6,3), B(3,8) and C(-6,10). If point D lies in quadrant II, find the coordinates of D.

Would anyone like to give it a go?